Répondre :
Bonsoir
[tex]\dfrac{1}{4}x^2-x-3=0\\\\\dfrac{1}{4}(x^2-4x-12)=0\\\\x^2-4x-12=0\\\\(x^2-4x+4)-4-12=0\\\\(x-2)^2-16=0\\\\(x-2)^2-4^2=0[/tex]
[tex][(x-2)-4][(x-2)+4]=0\\\\(x - 6)(x+2)=0\\\\x-6=0\ \ ou\ \ x+2=0\\\\x=6\ \ ou\ \ x=-2[/tex]
[tex]\dfrac{1}{4}x^2-x-3=0\\\\\dfrac{1}{4}(x^2-4x-12)=0\\\\x^2-4x-12=0\\\\(x^2-4x+4)-4-12=0\\\\(x-2)^2-16=0\\\\(x-2)^2-4^2=0[/tex]
[tex][(x-2)-4][(x-2)+4]=0\\\\(x - 6)(x+2)=0\\\\x-6=0\ \ ou\ \ x+2=0\\\\x=6\ \ ou\ \ x=-2[/tex]